In the inequality, what are all the possible values of x? 2(x + 12) − 16 ≤ 8 Responses A x < 0x < 0 B x ≤ 0x ≤ 0 C x ≥ 0x ≥ 0 D x ≤ 1
To solve the inequality, we will simplify the expression first.
2(x + 12) - 16 ≤ 8
Multiply 2 by x and 2 by 12:
2x + 24 - 16 ≤ 8
Combine like terms:
2x + 8 ≤ 8
Subtract 8 from both sides:
2x ≤ 0
Now, we divide both sides by 2:
x ≤ 0
Therefore, the correct answer is:
x ≤ 0
So, the answer is:
C) x ≤ 0