If 4/3,m,n... form a geometric progression the product of m and n is what
If 4/3, m, n form a geometric progression, this means that the ratio between each consecutive term is constant. Let's calculate the common ratio:
Common ratio = nth term / (n-1)th term
For the progression 4/3, m, n:
Common ratio = m / (4/3)
= m * (3/4)
Since this ratio is constant, we can set it equal to the ratio of n to m:
m * (3/4) = n / m
Multiplying both sides by m:
m^2 * (3/4) = n
The product of m and n is:
m * n = m * m^2 * (3/4) = (3/4) * m^3