Mark and Heather Starr are celebrating their 25th anniversary by having a reception at a local reception hall. They have budgeted $5,000 for their reception. If the reception hall charges a 560 cleanup lee plus $32 per person find the greatest number of people that they may invite and still stay within their budget
Let's assume the number of people they invite is x.
The cost of the reception hall is $560 + $32x.
According to the budget, $560 + $32x ≤ $5000.
We can subtract $560 from both sides of the inequality to get $32x ≤ $5000 - $560, which simplifies to $32x ≤ $4440.
To solve for x, we divide both sides of the inequality by $32: x ≤ $4440 / $32.
x ≤ 138.75.
The greatest number of people they may invite and still stay within their budget is 138 people.