The function p(d)=1+d/33, gives the pressure, in atmospheres (atm), at a depth d in the sea?
(d in in feet). Note that p(0)=1 atm, p(33)=2, and so on. Find the pressure at 40 feet
(Type answer as a integer or a simplified fraction.)
p(40) = 1 + 40/33
= (33 +40)/33
= 73/33
= 2 7/33
To find the pressure at 40 feet, we can substitute the value of d into the function p(d) = 1 + d/33:
p(40) = 1 + 40/33
Now, let's simplify:
p(40) = 1 + 40/33
p(40) = 33/33 + 40/33
p(40) = (33 + 40)/33
p(40) = 73/33
Therefore, the pressure at 40 feet is 73/33.
To find the pressure at 40 feet, we need to use the given function p(d) = 1 + d/33, where d is the depth in feet.
To find the pressure at 40 feet, substitute d = 40 into the function:
p(40) = 1 + 40/33
Now, let's simplify the expression:
p(40) = 1 + 40/33 = (33/33) + (40/33) = (33 + 40)/33 = 73/33
Therefore, the pressure at 40 feet is 73/33 atmospheres.