multiply:(2x-5)(3x^2-10x+8)

To multiply the expressions (2x-5)(3x^2-10x+8), we need to distribute the first expression (2x-5) to every term in the second expression (3x^2-10x+8).

Let's break it down step by step:

Multiplying 2x by every term in the second expression:
(2x)(3x^2) = 6x^3
(2x)(-10x) = -20x^2
(2x)(8) = 16x

Now let's multiply -5 by every term in the second expression:
(-5)(3x^2) = -15x^2
(-5)(-10x) = 50x
(-5)(8) = -40

Now we can add up all the terms we calculated:
6x^3 - 20x^2 + 16x - 15x^2 + 50x - 40

Combining like terms:
6x^3 - 35x^2 + 66x - 40

So the multiplication of (2x-5)(3x^2-10x+8) is equal to 6x^3 - 35x^2 + 66x - 40.