Use the periodic table to answer the question.
An illustration shows the periodic table of elements with elements arranged in increasing order of atomic number in 18 columns (groups) and 7 rows (periods). The electronegativity of elements increases from left to right, across a period. The hydrogen on the left is included in group with medium electronegativity. Also, fluorine is shown as element with highest electronegativity.
Based on patterns in the periodic table, which acid is strongest?
(1 point)
Responses
H2S
H 2 S
HBr
HBr
PH3
PH 3
HCl
HCl
To determine the strength of the acids based on patterns in the periodic table, we need to consider the electronegativity trend. The trend states that electronegativity increases from left to right across a period.
Looking at the options given, we can analyze the elements involved in each acid:
1. H2S: Hydrogen (H) and Sulfur (S)
2. HBr: Hydrogen (H) and Bromine (Br)
3. PH3: Phosphorus (P) and Hydrogen (H)
4. HCl: Hydrogen (H) and Chlorine (Cl)
Among these options, we can see that Fluorine (F) has the highest electronegativity value, and it is located in the top right corner of the periodic table. Therefore, we can expect Hydrogen Fluoride (HF) to be the strongest acid among these options. However, HF is not listed as one of the choices.
Comparing the given options, we can determine that HCl is the strongest acid. This is because Chlorine (Cl) is located to the right of Sulfur (S), Bromine (Br), and Phosphorus (P) in the periodic table, making it the most electronegative element among the given choices.