Find a third-degree polynomial equation with rational coefficients that has roots –4 and 6 + i.
(1 point)
Responses
x3 – 8x2 – 11x + 148 = 0
x 3 – 8 x 2 – 11 x + 148 = 0
x3 – 8x2 – 12x + 37 = 0
x 3 – 8 x 2 – 12 x + 37 = 0
x3 – 12x2 + 37x = 0
x 3 – 12 x 2 + 37 x = 0
x3 – 8x2 – 11x = 0
The correct equation is:
x^3 – 8x^2 – 11x + 148 = 0