The inside dimensions of Howard's semi-trailer are 52 feet long, 8.25 feet wide, and 9.25 feet tall. What is the carrying capacity of the trailer?
To find the carrying capacity of the trailer, we need to calculate the volume of the inside space.
The volume of a rectangular box can be found by multiplying its length, width, and height.
So, the volume of Howard's semi-trailer is 52 feet × 8.25 feet × 9.25 feet = 4,828.5 cubic feet.
Therefore, the carrying capacity of the trailer is 4,828.5 cubic feet.