If a right triangle has a leg that is 6ft long and the hypotenuse is 12ft long how long is the other leg round to the nearest tenth
To find the length of the other leg in a right triangle, we can use the Pythagorean theorem.
The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the other two sides.
In this case, we are given that one leg is 6ft long and the hypotenuse is 12ft long. Let's denote the length of the other leg as x.
According to the Pythagorean theorem:
x^2 + 6^2 = 12^2
x^2 + 36 = 144
x^2 = 144 - 36
x^2 = 108
To find the value of x, we take the square root of both sides of the equation:
x = √108
x ≈ 10.39
Rounded to the nearest tenth, the length of the other leg is approximately 10.4ft.
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To find the length of the other leg of a right triangle, we can use the Pythagorean theorem, which states that the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the other two sides.
In this case, we are given the length of one leg (6ft) and the length of the hypotenuse (12ft). Let's call the length of the other leg "x".
According to the Pythagorean theorem, we can set up the equation as:
(6^2) + (x^2) = (12^2)
Simplifying this equation, we get:
36 + x^2 = 144
To solve for x, we need to isolate x^2 by subtracting 36 from both sides of the equation:
x^2 = 144 - 36
x^2 = 108
Now, we can take the square root of both sides to solve for x:
x = √108
Calculating the square root of 108, we get:
x ≈ 10.3923
Finally, rounding to the nearest tenth, the length of the other leg is approximately 10.4ft.