(x+2y)(x^2-xy+3y)
Expanding the given expression, we have:
(x+2y)(x^2-xy+3y)
= x(x^2-xy+3y) + 2y(x^2-xy+3y)
= x^3 - x^2y + 3xy + 2xy^2 - 2xy^2 + 6y^2
= x^3 - x^2y + 5xy + 6y^2
Thus, (x+2y)(x^2-xy+3y) expands to x^3 - x^2y + 5xy + 6y^2.
(x+2y)(x^2-xy+3y)
= x(x^2-xy+3y) + 2y(x^2-xy+3y)
= x^3 - x^2y + 3xy + 2xy^2 - 2xy^2 + 6y^2
= x^3 - x^2y + 5xy + 6y^2
Thus, (x+2y)(x^2-xy+3y) expands to x^3 - x^2y + 5xy + 6y^2.