A display has
\[6\] packs of marbles with a total mass of
\[629\,\text{g}\]. The packaging of each pack has a mass of
\[\dfrac{2}{3}\,\text{g}\] and each marble has a mass of
\[4\dfrac{1}{2}\,\text{g}\].
Which equation can we use to determine
\[m\], the number of marbles per pack?
Choose 1 answer:
Choose 1 answer:
(Choice A)
\[6\cdot 4\dfrac{1}{2}m+\dfrac{2}{3}=629\]
A
\[6\cdot 4\dfrac{1}{2}m+\dfrac{2}{3}=629\]
(Choice B)
\[6m\left(4\dfrac{1}{2}+\dfrac{2}{3}\right)=629\]
B
\[6m\left(4\dfrac{1}{2}+\dfrac{2}{3}\right)=629\]
(Choice C)
\[6m+4\dfrac{1}{2}+\dfrac{2}{3}=629\]
C
\[6m+4\dfrac{1}{2}+\dfrac{2}{3}=629\]
(Choice D)
\[6\left(4\dfrac{1}{2}m+\dfrac{2}{3}\right)=629\]
D
\[6\left(4\dfrac{1}{2}m+\dfrac{2}{3}\right)=629\]
The total mass of the marbles and packaging is equal to the total mass of the packs of marbles, so we can set up the equation:
\[(\text{mass of each marble})(\text{number of marbles per pack}) + (\text{mass of packaging}) = (\text{total mass of packs of marbles})\]
Substituting the given values, we get:
\[4\frac{1}{2}m + \frac{2}{3} = 629\]
So, the answer is $\boxed{\text{(A)} \: 6\cdot 4\frac{1}{2}m+\frac{2}{3}=629}$.
so whats the answer a b c or d
The answer is $\boxed{\text{(A)} \: 6\cdot 4\frac{1}{2}m+\frac{2}{3}=629}$.
To determine the number of marbles per pack, we need to set up an equation using the given information.
Let's break down the information provided:
- There are 6 packs of marbles.
- The total mass of the 6 packs is 629g.
- The packaging of each pack has a mass of 2/3g.
- Each marble has a mass of 4 1/2g.
To determine the number of marbles per pack, we can use the equation:
(Number of packs) x (Mass of each pack + Mass of each marble) + (Mass of packaging) = Total mass
Let's substitute the given information into the equation:
6m(4 1/2 + 2/3) + 2/3 = 629
Now, let's simplify the equation to its correct form:
Choice B) 6m(4 1/2 + 2/3) = 629
Therefore, the correct equation to determine m, the number of marbles per pack, is Choice B) 6m(4 1/2 + 2/3) = 629.