What is the coefficient of static friction between a load of mass 0.75kg and a horizontal surface if the limiting frictional force is 5N(g=10m/s2)
The coefficient of static friction can be determined using the formula:
μs = Fs / N
where μs is the coefficient of static friction, Fs is the limiting frictional force, and N is the normal force exerted by the surface.
In this case, the normal force (N) can be calculated using Newton's second law:
N = mg
where m is the mass of the load and g is the acceleration due to gravity.
Given:
m = 0.75 kg
Fs = 5 N
g = 10 m/s^2
N = (0.75 kg)(10 m/s^2)
N = 7.5 N
Now, we can substitute the values into the equation for the coefficient of static friction:
μs = Fs / N
μs = 5N / 7.5N
μs = 0.67
Therefore, the coefficient of static friction between the load and the horizontal surface is 0.67.