A block of a weight 200N rest on a rough horizontal table. When the block just being to slip the pulling force is found to be 40N. What is the coefficient of friction (N) between the surface (g=10m/s)
To find the coefficient of friction, we need to use the equation:
frictional force = coefficient of friction * normal force
The normal force is equal to the weight of the block, which is 200N.
Since the block is on the verge of slipping, the force required to overcome friction is equal to the force applied (pulling force) plus the frictional force.
So, the total force required to overcome friction is 40N + frictional force.
Setting up the equation:
40N + frictional force = frictional force * 200N
Rearranging the equation:
40N = frictional force * (200N - 1)
40N = frictional force * 199N
Divide both sides of the equation by 199N:
frictional force = 40N / 199N = 0.201N
Now we can substitute the value of the frictional force into the first equation:
0.201N = coefficient of friction * 200N
Divide both sides of the equation by 200N:
coefficient of friction = 0.201N / 200N = 0.001005
Therefore, the coefficient of friction between the surface and the block is approximately 0.001005.