Which of the following is a point on the graph as described by the function y=(2x+1)2−4 ?(1 point) Responses (1,2) left parenthesis 1 comma 2 right parenthesis (−1,−5) left parenthesis negative 1 comma negative 5 right parenthesis (−1,−3) left parenthesis negative 1 comma negative 3 right parenthesis (0,−2)
To find the point on the graph, we can substitute the x-coordinate into the equation and solve for y.
For option (1,2):
x = 1
y = (2(1) + 1)^2 - 4
y = (2+1)^2 - 4
y = 3^2 - 4
y = 9 - 4
y = 5
So, (1,2) is not a point on the graph.
For option (-1,-5):
x = -1
y = (2(-1) + 1)^2 - 4
y = (-2+1)^2 - 4
y = (-1)^2 - 4
y = 1 - 4
y = -3
So, (-1,-5) is not a point on the graph.
For option (-1,-3):
x = -1
y = (2(-1) + 1)^2 - 4
y = (-2+1)^2 - 4
y = (-1)^2 - 4
y = 1 - 4
y = -3
So, (-1,-3) is a point on the graph y = (2x+1)^2 - 4.
For option (0,-2):
x = 0
y = (2(0) + 1)^2 - 4
y = (0+1)^2 - 4
y = (1)^2 - 4
y = 1 - 4
y = -3
So, (0,-2) is not a point on the graph.
Therefore, the point on the graph described by the function y = (2x+1)^2 - 4 is (-1,-3).