Illustrate a scientific conceptual image showing a system where a steel cable is holding a 355kg cargo load. Ensure the visuals underline the forces at play in scenarios A and B, while avoiding any text. Scenario A represents the cargo in a stationary position where tension and weight are in balance. Scenario B signifies the cargo accelerating upward at a rate of 0.25 m/(s^2) where the tension is increased. Use symbolic representation for tension (FT) and weight (W) with visual cues to explain the phenomena.

Given DIAGRAM 1.1 where FT means Tension and W means Weight, calculate the tension on the steel cable given the following conditions:

A. The cargo is stationary.
B. The cargo accelerates upward at a rate of 0.25 m/(s^2)

Steel Cable 355kg cargo

What is the tension in Condition A?

In Condition A, when the cargo is stationary, the tension in the steel cable is equal to the weight of the cargo.

To find the tension, we need to calculate the weight of the cargo.

Weight = mass × acceleration due to gravity

Given:
Mass of the cargo = 355 kg
Acceleration due to gravity (g) = 9.8 m/s^2

Weight = 355 kg × 9.8 m/s^2

Weight = 3481 N

Therefore, the tension in Condition A is 3481 N.