A 45 kg person jumps off a diving platform 10.0 m above the water. If they reach the surface of the water at a speed of 12 m/s, what is the person's kinetic energy?
The formula to calculate kinetic energy is:
KE = 1/2 * m * v^2
Where:
KE = Kinetic energy
m = Mass
v = Velocity
Given that the mass of the person is 45 kg and the speed is 12 m/s:
KE = 1/2 * 45 kg * (12 m/s)^2
KE = 1/2 * 45 kg * 144 m^2/s^2
KE = 0.5 * 45 kg * 144 m^2/s^2
KE = 3240 kg m^2/s^2
Therefore, the person's kinetic energy is 3240 kg m^2/s^2.