Two bowling balls of different masses collide while accelerating at 1.875 m/s 2 . The first ball, rolling to the right, weighs 7 kg. The second ball, rolling to the left, weighs 4 kg. What force does the bowling ball weighing 7 kg exert on the bowling ball weighing 4 kg?(1 point) Responses 7.5 N to the left 7.5 N to the left 13.125 N to the right 13.125 N to the right 8.875 N to the right 8.875 N to the right 3.73 N to the right
To solve this problem, we can use Newton's second law of motion, which states that the force exerted on an object is equal to the mass of the object multiplied by its acceleration.
First, we need to calculate the force acting on the 7 kg ball. Using the formula F = m*a, where mass (m) is 7 kg and acceleration (a) is 1.875 m/s^2, we get F1 = 7 kg * 1.875 m/s^2 = 13.125 N to the right.
Since the two balls collide, the force exerted by the 7 kg ball on the 4 kg ball will be equal in magnitude but opposite in direction. Therefore, the force exerted on the 4 kg ball by the 7 kg ball is 13.125 N to the left.
Therefore, the correct answer is 13.125 N to the left.