2Hg + O2---> 2HgO If the total mass of the product, mercuric oxide, HgO, is 433.2 grams, what is the total mass of the Mercury and Oxygen on the reactants side of the equation? Type your answer in the below box.
The total mass of the product, mercuric oxide (HgO), is 433.2 grams. Since there are two mercury atoms in one molecule of HgO, we can assume that the total mass of the mercury atoms is twice the mass of the HgO.
Let's denote the mass of one molecule of HgO as m(HgO). Then, the mass of two mercury atoms is 2 * m(HgO).
Since the total mass of the product, HgO, is 433.2 grams, we can write the equation:
2 * m(HgO) = 433.2 grams
Solving for m(HgO), we can divide both sides of the equation by 2:
m(HgO) = 433.2 grams / 2
m(HgO) = 216.6 grams
Therefore, the total mass of the mercury and oxygen on the reactants side of the equation is 216.6 grams.
216.6 is wrong, please try again
I apologize for the error. Let's try again.
In the balanced chemical equation 2Hg + O2 -> 2HgO, the ratio of mercury to mercuric oxide is 2:2, or 1:1. This means that the mass of the mercury and oxygen on the reactants side of the equation is also equal to the mass of the mercuric oxide.
Therefore, the total mass of the mercury and oxygen on the reactants side of the equation is 433.2 grams.
are you sure
You are correct, I apologize for the mistake in my previous response. Let's reassess the problem.
In the balanced chemical equation 2Hg + O2 -> 2HgO, we have 2 moles of mercury (Hg) reacting with 1 mole of oxygen (O2) to form 2 moles of mercuric oxide (HgO).
To determine the total mass of the mercury and oxygen on the reactants side of the equation, we need to calculate the molar mass of mercuric oxide (HgO) and then multiply it by the number of moles.
The molar mass of HgO can be calculated by summing the atomic masses of mercury (Hg) and oxygen (O) in one mole of HgO.
Using the atomic masses from the periodic table, we have:
Atomic mass of Hg = 200.59 g/mol
Atomic mass of O = 16.00 g/mol
So, the molar mass of HgO = (200.59 g/mol) + (16.00 g/mol) = 216.59 g/mol
Since the total mass of the product, HgO, is given as 433.2 grams, we can calculate the number of moles of HgO:
Number of moles = mass / molar mass
Number of moles of HgO = 433.2 g / 216.59 g/mol ≈ 2 moles
As the balanced equation shows that 2 moles of HgO are formed from 2 moles of Hg and 1 mole of O2, the total mass of the mercury and oxygen on the reactants side of the equation is:
Total mass = (2 moles of Hg + 1 mole of O2) x molar mass of HgO
Total mass = (2 x 200.59 g/mol) + (1 x 32.00 g/mol) = 401.18 g/mol + 32.00 g/mol ≈ 433.18 g
Therefore, the total mass of the mercury and oxygen on the reactants side of the equation is approximately 433.18 grams. I apologize for the earlier incorrect response.
To find the total mass of mercury and oxygen on the reactants' side of the equation, we need to balance the equation first. We can do this by assigning coefficients to each compound in the equation that balance the number of atoms on both sides.
The balanced equation will look like this:
2Hg + O2 → 2HgO
From the equation, we can see that for every 2 molecules of mercury (Hg), we need 1 molecule of oxygen gas (O2) to form 2 molecules of mercuric oxide (HgO).
Now that we have the balanced equation, we can calculate the total mass of mercury and oxygen.
The molecular weight of mercury (Hg) is 200.59 g/mol, and the molecular weight of oxygen (O2) is 32 g/mol.
Using these molecular weights, we can calculate the molar mass and moles of each element present:
- Mercury (Hg): 2Hg x 200.59 g/mol = 401.18 g
- Oxygen (O2): 1 molecule of O2 x 32 g/mol = 32 g
Therefore, the total mass of mercury and oxygen on the reactants' side of the equation is:
401.18 g + 32 g = 433.18 g
So, the total mass is approximately 433.18 grams.