Two bowling balls of different masses collide while accelerating at 1.875 m/s 2
. The first ball, rolling to the right, weighs 7 kg. The second ball, rolling to the left, weighs 4 kg. What force does the bowling ball weighing 7 kg exert on the bowling ball weighing 4 kg?
Responses
8.875 N to the right
8.875 N to the right
13.125 N to the right
13.125 N to the right
7.5 N to the left
7.5 N to the left
3.73 N to the right
To find the force exerted by the bowling ball weighing 7 kg on the bowling ball weighing 4 kg, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a).
We already have the mass of the first ball (m1 = 7 kg) and the acceleration (a = 1.875 m/s^2). To find the force exerted by the first ball, we plug these values into the formula:
F1 = m1 * a
F1 = 7 kg * 1.875 m/s^2
F1 = 13.125 N
Therefore, the first ball exerts a force of 13.125 N. Since the first ball is rolling to the right and the second ball is rolling to the left, the force exerted by the first ball on the second ball is in the opposite direction. So, the force exerted by the bowling ball weighing 7 kg on the bowling ball weighing 4 kg is 13.125 N to the left.
The correct response is: 13.125 N to the left.