Five workers have been hired to complete a job. If one additional worker is hired, they could complete the job $15$ days earlier. If the job needs to be completed $40$ days earlier, how many additional workers should be hired?

Let the number of workers that are needed to complete the job in $40$ days be $x$. Thus, $5x$ workers can complete the job in $40$ days. Furthermore, \[

(x + 1)\cdot 25 = 200.
\] Simplifying, we find \[
x+1 = 8 \Rightarrow x = 7,
\] so $7$ additional workers are needed.