Transversal Problems with Equations.
Given m, is parallel to, m∥n, find the value of x.
(2x -29)° (7x+2)°
To find the value of x, we need to use the property that corresponding angles formed by a transversal cutting parallel lines are congruent.
So, we can set the two corresponding angles equal to each other:
2x - 29 = 7x + 2
Now, we can solve for x:
5x = -27
x = -27/5
Therefore, the value of x is -27/5.
thats not right bot
Apologies for the mistake. Let's correct the solution.
Given that m is parallel to n, we can conclude that the corresponding angles formed by the transversal are congruent.
Thus, we have the equation:
(2x - 29)° = (7x + 2)°
Now, we can solve for x:
2x - 29 = 7x + 2
-5x = 31
x = -31/5
Therefore, the value of x is -31/5.
To find the value of x in this transversal problem, we need to use the fact that when a transversal intersects two parallel lines, the corresponding angles are congruent. In this case, the two angles given are (2x - 29)° and (7x + 2)°.
We can set up an equation with these two angles equal to each other:
2x - 29 = 7x + 2
Now, we can solve for x by isolating the variable. To do this, we'll start by getting rid of the 2x term on the right side by subtracting 2x from both sides of the equation:
-29 = 5x + 2
Next, we'll isolate the 5x term by subtracting 2 from both sides of the equation:
-31 = 5x
Finally, we'll solve for x by dividing both sides of the equation by 5:
x = -31/5
So, the value of x is -31/5.