The sum of two number is 18 .five times the first number subtracted from four over seven of the second number is 14 .find the number
Let's call the first number x and the second number y.
According to the problem, the sum of these two numbers is 18:
x + y = 18 ----(1)
The second part of the problem states that "five times the first number subtracted from four over seven of the second number is 14":
(4/7)y - 5x = 14 ----(2)
Now, we have two equations with two unknowns. We can solve this system of equations by substitution or elimination.
Using substitution, we can solve equation (1) for x:
x = 18 - y
Substituting this value of x into equation (2), we get:
(4/7)y - 5(18 - y) = 14
Expanding and simplifying the equation:
(4/7)y - 90 + 5y = 14
Combining like terms:
(4/7)y + 5y = 14 + 90
Multiplying by 7 to eliminate the fractions:
4y + 35y = 98 + 630
39y = 728
Dividing both sides by 39:
y = 728/39
Simplifying:
y ≈ 18.67
Now, we can substitute this value of y back into equation (1) to find x:
x + 18.67 = 18
Subtracting 18.67 from both sides:
x = 18 - 18.67
Simplifying:
x ≈ -0.67
Therefore, the first number is approximately -0.67 and the second number is approximately 18.67.