Starting from 50 miles away, a car drives toward a speed checkpoint and then passes it. The car travels at a constant rate of 30 miles per hour.
The distance of the car from the checkpoint is given by `d=\left|50=30t\right|.`
At what times is the car 5 miles from the checkpoint?
To find the times when the car is 5 miles from the checkpoint, we can substitute d = 5 into the equation and solve for t.
5 = |50 - 30t|
Since the expression inside the absolute value signs can only be positive, we have:
5 = 50 - 30t
Subtracting 50 from both sides, we get:
-45 = -30t
Dividing both sides by -30, we have:
t = 1.5
Therefore, the car is 5 miles from the checkpoint at times t = 1.5 hours.