Find the second, fourth, and tenth terms of the sequence described by the rule.
A(n)=12+(n-1)(2)
To find the second term, we substitute $n=2$ into the rule to get $A(2)=12+(2-1)(2)=12+2(2)=12+4=\boxed{16}$.
To find the fourth term, we substitute $n=4$ into the rule to get $A(4)=12+(4-1)(2)=12+3(2)=12+6=\boxed{18}$.
To find the tenth term, we substitute $n=10$ into the rule to get $A(10)=12+(10-1)(2)=12+9(2)=12+18=\boxed{30}$.