A rectangular park has an area of 1.36 x 10° ft?. The length of the park is 1.6 × 104 ft. Divide the area by the
length to find the width of the park. (1 point)
O 8.5 x 104 ft.
O 8.5 x 103 ft.
O 8.5 x 103 Ht.
O 8.5 x 105 ft
To find the width of the park, we need to divide the area by the length.
Area = 1.36 x 10^0 ft^2
Length = 1.6 x 10^4 ft
Width = Area / Length
Width = (1.36 x 10^0 ft^2) / (1.6 x 10^4 ft)
To divide numbers in scientific notation, we subtract the exponents: 0 - 4 = -4
Width = 1.36 / (1.6 x 10^4) ft^(0-4)
Width = 1.36 / (1.6 x 10^-4) ft
To multiply numbers in scientific notation, we multiply the coefficients and add the exponents: 1.36 / 1.6 = 0.85 and 10^0 x 10^-4 = 10^-4
Width = 0.85 x 10^-4 ft = 8.5 x 10^-5 ft
Therefore, the width of the park is 8.5 x 10^-5 ft, which is equivalent to 8.5 x 10^(-5+2) ft = 8.5 x 10^-3 ft.
The correct answer is 8.5 x 10^-3 ft or 8.5 x 10^3 ft. (Option B)
Divide 3.3 x 104 by 5.5 x 107. (1 point)
0 6 x10-4
0 6 x 10-3
O 6 x 10-6
O 6x 10-5
To divide numbers in scientific notation, we divide the coefficients and subtract the exponents.
3.3 x 10^4 / 5.5 x 10^7 = (3.3 / 5.5) x 10^(4-7)
3.3 / 5.5 = 0.6
10^(4-7) = 10^-3 (subtracting exponents)
Therefore, 3.3 x 10^4 / 5.5 x 10^7 = 0.6 x 10^-3 = 6 x 10^-4
The correct answer is 6 x 10^-4. (Option A)
A city lunch program for seniors received a grant of 1.925 × 10® dollars. Divide that figure by the cost of $2.75
per lunch to find out how many senior lunches the grant can provide. Write the answer in scientific notation.
(1 point)
0 7 × 105
0 7 × 106
O 0.7 × 105
0 0.7×106
To find out how many senior lunches the grant can provide, we need to divide the grant amount by the cost per lunch.
Grant amount = 1.925 x 10^9 dollars
Cost per lunch = $2.75
Number of senior lunches = Grant amount / Cost per lunch
Number of senior lunches = (1.925 x 10^9 dollars) / ($2.75)
To divide numbers in scientific notation, we divide the coefficients and subtract the exponents:
Number of senior lunches = 1.925 x 10^9 / 2.75 = 0.7 x 10^9
Since 0.7 x 10^9 can be written as 7 x 10^8, the answer is 7 x 10^8.
The correct answer is 7 x 10^8. (Option B)
A city lunch program for seniors received a grant of 1.925 × 10--> 6 dollars. Divide that figure by the cost of $2.75
per lunch to find out how many senior lunches the grant can provide. Write the answer in scientific notation.
(1 point)
0 7 × 10 5
0 7 × 10 6
O 0.7 × 10 5
0 0.7×10 6
To find the number of senior lunches the grant can provide, we need to divide the grant amount by the cost per lunch.
Grant amount = 1.925 x 10^6 dollars
Cost per lunch = $2.75
Number of senior lunches = Grant amount / Cost per lunch
Number of senior lunches = (1.925 x 10^6 dollars) / ($2.75)
To divide numbers in scientific notation, we divide the coefficients and subtract the exponents:
Number of senior lunches = 1.925 x 10^6 / 2.75 = 0.7 x 10^6
Since 0.7 x 10^6 can be written as 7 x 10^5, the answer is 7 x 10^5.
The correct answer is 7 x 10^5. (Option A)
Solomon needs to distribute 10.5 gallons of perfume among 3.5 x10? containers. How manv gallons of
perfume will be in each container? Write the answer in scientific notation. (1 point)
O 3 x 10-1
O 3 x 10-2
O 0.35 x 10-1
0 3 x 103
To find out how many gallons of perfume will be in each container, we need to divide the total amount of perfume by the number of containers.
Total amount of perfume = 10.5 gallons
Number of containers = 3.5 x 10^1
Amount of perfume per container = Total amount of perfume / Number of containers
Amount of perfume per container = 10.5 gallons / (3.5 x 10^1)
To divide numbers in scientific notation, we divide the coefficients and subtract the exponents:
Amount of perfume per container = 10.5 / 3.5 = 3
10^1 / 10^1 = 1 (subtracting exponents)
Therefore, the answer is 3 x 10^0 gallons.
Since 10^0 is equal to 1, the answer can be simplified to just 3 gallons.
The correct answer is 3 gallons.
A large pavilion is made of 2.967 x 105 bricks. There are 6.9 bricks per square foot. How many square feet is thi
pavilion? Write the answer in scientific notation. (1 point)
O 4.3 x 104
O 2.33 x 105
O 0.43 x 104
O 4.3 × 105