When a regular polygon with n sides is decomposed into triangles using the same vertex, how many triangles are formed?(1 point)

Responses

When a regular polygon is decomposed, n triangles are formed, where n is the number of sides of the regular polygon.
When a regular polygon is decomposed, n triangles are formed, where n is the number of sides of the regular polygon.

When a regular polygon is decomposed, n+2 triangles are formed, where n is the number of sides of the regular polygon. There are two more triangles than the number of the sides of the regular polygon.
When a regular polygon is decomposed, n plus 2 triangles are formed, where n is the number of sides of the regular polygon. There are two more triangles than the number of the sides of the regular polygon.

When a regular polygon is decomposed, n−2 triangles are formed, where n is the number of sides of the regular polygon. There are two fewer triangles than the number of the sides of the regular polygon.
When a regular polygon is decomposed, n minus 2 triangles are formed, where n is the number of sides of the regular polygon. There are two fewer triangles than the number of the sides of the regular polygon.

When a regular polygon is decomposed, 2⋅n triangles are formed, where n is the number of sides of the regular polygon. There are twice as many triangles formed than the number of the sides of the regular polygon.

When a regular polygon with n sides is decomposed using the same vertex, n-2 triangles are formed. There are two fewer triangles than the number of sides of the regular polygon.