Calculate the heat given off when 104.1 g of copper cools from 155.0oC to 23.0oC. The specific heat capacity of copper is 0.385 J/g oC.

To calculate the heat given off, we need to use the formula:

q = m × c × ΔT

where:
q = heat given off
m = mass of copper (104.1 g)
c = specific heat capacity of copper (0.385 J/g °C)
ΔT = change in temperature (final temperature - initial temperature)

By substituting the given values:

ΔT = 23.0 °C - 155.0 °C = -132.0 °C (we get a negative value because the temperature is decreasing)
q = 104.1 g × 0.385 J/g°C × -132.0 °C

q = -5181.78 J

Therefore, the heat given off is -5181.78 J (or you can simply write it as 5182 J, since the negative sign indicates that heat is being released).

a

The heat given off when 104.1 g of copper cools from 155.0°C to 23.0°C is 5182 J.

how do you know this

To calculate the heat given off, we can use the formula:

q = m × c × ΔT

where:
q = heat given off
m = mass of copper (104.1 g)
c = specific heat capacity of copper (0.385 J/g °C)
ΔT = change in temperature (final temperature - initial temperature)

By substituting the given values:

ΔT = 23.0 °C - 155.0 °C = -132.0 °C (we get a negative value because the temperature is decreasing)
q = 104.1 g × 0.385 J/g °C × -132.0 °C

q = -5181.78 J

Therefore, the heat given off is -5181.78 J (or we can write it as 5182 J, since the negative sign indicates that heat is being released).

To calculate the heat given off when copper cools, you can use the formula:

Q = mcΔT

where:
Q = heat given off (in joules)
m = mass of the substance (in grams)
c = specific heat capacity (in J/g oC)
ΔT = change in temperature (in oC)

In this problem, the mass of copper is given as 104.1 g, the specific heat capacity is 0.385 J/g oC, and the change in temperature is from 155.0oC to 23.0oC.

Substituting these values into the formula:

Q = (104.1 g) x (0.385 J/g oC) x (23.0oC - 155.0oC)

Now, let's calculate ΔT:

ΔT = 23.0oC - 155.0oC
ΔT = -132.0oC

Plugging this value back into the formula:

Q = (104.1 g) x (0.385 J/g oC) x (-132.0oC)
Q = -6494.92 J

The heat given off when the copper cools from 155.0oC to 23.0oC is approximately -6494.92 J. The negative sign indicates that heat is being released or given off.