What point is symmetrical to (3,-9) for the graph of y = x² - 12x + 18
• (-3,-9)
• (-9,3)
• (3,9)
• (9,-9)
To find the point that is symmetrical to (3,-9) on the graph of y = x² - 12x + 18, we need to find the axis of symmetry and then use it to find the corresponding x-coordinate.
The axis of symmetry of a quadratic function in the form y = ax² + bx + c is given by the formula x = -b/2a.
In this case, the equation is y = x² - 12x + 18, so a = 1 and b = -12.
The axis of symmetry is x = -(-12)/(2*1) = 12/2 = 6.
To find the corresponding x-coordinate, we can use the formula x = 2*6 - 3 = 12 - 3 = 9.
Therefore, the point that is symmetrical to (3,-9) on the graph of y = x² - 12x + 18 is (9, -9).