write a balanced chemical equation with symbols for liquid butane combusting with oxygen gas to produce 2 gases. be sure to include a complete reactant and product side of equation.
C4H10 + 13O2 -> 8CO2 + 10H2O
csnyder194
I apologize for the confusion, but it seems like your response does not correspond to the initial request. However, if you have any specific questions or need assistance with anything else, feel free to ask!
To write a balanced chemical equation, we need to consider the conservation of mass. This means that the number of atoms of each element should be the same on both sides of the equation. In this case, we have liquid butane (C₄H₁₀) combusting with oxygen gas (O₂) to produce two gases.
The balanced chemical equation for this reaction would be:
2C₄H₁₀ (l) + 13O₂ (g) -> 8CO₂ (g) + 10H₂O (g)
Let's break it down step by step:
1. Start by balancing the carbon (C) atoms. There are 8 carbon atoms on the product side, so we need to place a coefficient 2 in front of C₄H₁₀ on the reactant side.
2C₄H₁₀ (l) + ___O₂ (g) -> 8CO₂ (g) + ___H₂O (g)
2. Next, balance the hydrogen (H) atoms. There are 20 hydrogen atoms on the product side, so we place a coefficient 5 in front of H₂O on the reactant side.
2C₄H₁₀ (l) + ___O₂ (g) -> 8CO₂ (g) + 5H₂O (g)
3. Now, consider the oxygen (O) atoms. On the reactant side, there are 13 oxygen atoms from O₂ and 5 oxygen atoms from H₂O, making a total of 18 oxygen atoms. Therefore, we need to balance the oxygen atoms on the product side by placing a coefficient 13/2 (which can be multiplied by 2 to give a whole number) in front of O₂.
2C₄H₁₀ (l) + 13/2O₂ (g) -> 8CO₂ (g) + 5H₂O (g)
However, coefficients in chemical equations should always be written as whole numbers. So, to make the equation simpler, we can multiply all coefficients by 2:
4C₄H₁₀ (l) + 13O₂ (g) -> 16CO₂ (g) + 10H₂O (g)
Therefore, the balanced chemical equation for the combustion of liquid butane (C₄H₁₀) with oxygen gas (O₂) to produce carbon dioxide (CO₂) and water (H₂O) gases is:
4C₄H₁₀ (l) + 13O₂ (g) -> 16CO₂ (g) + 10H₂O (g)