What is the smallest number which has 6, 8, 12 as factors
To find the smallest number that has 6, 8, and 12 as factors, we need to find their least common multiple (LCM).
First, let's factorize each number:
6 = 2 * 3
8 = 2 * 2 * 2
12 = 2 * 2 * 3
From their factorizations, we can take the highest power of every prime factor that appears in any of the numbers. In this case, the highest power of 2 is 3 and the highest power of 3 is 1.
Thus, the LCM of 6, 8, and 12 is 2^3 * 3^1 = 8 * 3 = 24.
Therefore, the smallest number that has 6, 8, and 12 as factors is 24.