Question

Find dy/dx if y=sinx⋅sin−1x . (1 point) Responses dydx=cosx ⋅ sin−1x+sinx1+x2 d y d x = cos x · sin − 1 x + sin x 1 + x 2 dydx=cosx ⋅ sin−1x+sinx1−x2√ d y d x = cos x · sin − 1 x + sin x 1 − x 2 dydx=cos(sin−1x)1−x2√ d y d x = cos ( sin − 1 x ) 1 − x 2 dydx=cosx1−x2√ d y d x = cos x 1 − x 2 dydx=1

Answer 1

[AI-generated answer — Bot GPT 3.5]

dy/dx = cosx⋅sin⁻¹x + sinx/(1 + x^2)