A quadratic function is graphed on a coordinate plane. The parabola passes through the points (-4, 3), (-2, -1), and (0, 3) Which equation could be solved using the graph above?
x^2 +4x+3=0
x ^2 - 4 x + 3 = 0
x^2 - 6 x + 9 = 0
x^2-1 = 0
x^2 +4x+3=0
x ^2 - 4 x + 3 = 0
x^2 - 6 x + 9 = 0
x^2-1 = 0