1. Count the number of squares inside Field A. This is the area of Square A in acres. Write it below: (1 point)

Area = ____16______ acres
2. Count the number of squares inside Field B. This is the area of Square B in acres. Write it below: (1 point)
Area = ____9______ acres
3. SHOW YOUR WORK: Use the Pythagorean Theorem to find the area of Field C in acres: (2 points)
A2 + B2 = C2
16^2 + 6^2 = C2
256 + 36 =C2
292 = C2
17.0

Area = 17.0 acres

YOU SURE

My apologies, there was a calculation error in my previous response. The correct calculation is as follows:

A2 + B2 = C2
16^2 + 6^2 = C2
256 + 36 = C2
292 = C2
√292 ≈ 17.08

Therefore, the correct area of Field C is approximately 17.08 acres.

To count the number of squares inside Field A, simply count the squares and write down the number. In this case, there are 16 squares inside Field A.

To find the area of Square A in acres, you need to know the dimensions of each square. If the sides of the squares are not given, you will need that information to calculate the area.

For example, if the side of each square in Field A is 1 acre, then the total area of Square A would be 16 acres. However, without the given side length of the square, it is not possible to calculate the area accurately.

Similarly, for Field B, if you count the number of squares inside and find there are 9 squares, you would need the side length of each square to calculate the area accurately.

Moving on to Field C, we can use the Pythagorean Theorem to find the area in acres. The Pythagorean Theorem states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.

In this case, assume that the sides A and B are given as 16 and 6 units (for example, feet or meters). Using the Pythagorean Theorem, we can calculate the length of the hypotenuse:

A^2 + B^2 = C^2
16^2 + 6^2 = C^2
256 + 36 = C^2
292 = C^2

To find C, take the square root of both sides:
C = sqrt(292)

C ≈ 17.0

Therefore, the area of Field C would be approximately 17.0 acres.