subtract (8x+2) from the sum of (6x+10) and (3x+12)
To subtract (8x+2) from the sum of (6x+10) and (3x+12), we first need to find the sum of (6x+10) and (3x+12):
(6x+10) + (3x+12)
To simplify this expression, we can combine like terms:
6x + 3x + 10 + 12
Combining like terms, we have:
9x + 22
Now, we can subtract (8x+2) from 9x + 22:
(9x + 22) - (8x + 2)
To subtract, we distribute the negative sign to each term inside the parentheses:
9x + 22 - 8x - 2
Now, we can combine like terms:
(9x - 8x) + (22 - 2)
9x - 8x is equal to x, and 22 - 2 is equal to 20.
So, the final result is:
x + 20