Adrian’s lawn mower run a fuel combination of oil and gasoline the table shows the amount of oil Adrian’s mixin with the amount of gasoline
Amount of oil l liters 0.05 0.10 0.15 0.2 0.25
Amount of gasoline g in liters 1.6 3.2 4.8 6.4 8
Answers
G=32l
G= l +3.2
L=32g
L=g +3.2
It seems like there is a mistake in the given equations.
Corrected equations:
1) G = 32L
2) G = L + 3.2
3) L = 32G
4) L = G + 3.2
Explanation:
- The first equation says that the amount of gasoline (G) in liters is 32 times the amount of oil (L) in liters.
- The second equation suggests that the amount of gasoline (G) in liters is equal to the amount of oil (L) in liters plus 3.2 liters.
- The third equation states that the amount of oil (L) in liters is 32 times the amount of gasoline (G) in liters.
- The fourth equation suggests that the amount of oil (L) in liters is equal to the amount of gasoline (G) in liters plus 3.2 liters.
These equations describe the relationship between the amount of oil and gasoline mixtures.
To find the relationship between the amount of oil (L) and the amount of gasoline (G) in this fuel mixture, we can use the information from the table.
The table shows different amounts of oil (in liters) mixed with different amounts of gasoline (also in liters).
In the first row, the amount of oil is given as 0.05 liters, and in the corresponding column, the amount of gasoline is 1.6 liters.
Similarly, in the second row, the amount of oil is 0.10 liters, and in the corresponding column, the amount of gasoline is 3.2 liters.
We can observe that the ratio of oil to gasoline remains constant for each row. For example, for every 0.05 liters of oil, there are 1.6 liters of gasoline; for every 0.10 liters of oil, there are 3.2 liters of gasoline, and so on.
This constant ratio allows us to establish a relationship between the amount of oil (L) and the amount of gasoline (G).
To convert the given table into a mathematical equation, we can rewrite the ratio as follows:
L/0.05 = G/1.6
L/0.10 = G/3.2
L/0.15 = G/4.8
L/0.20 = G/6.4
L/0.25 = G/8.0
To simplify the equation, we can rearrange it and multiply both sides of each equation by the denominators:
L = (0.05/1.6)G
L = (0.10/3.2)G
L = (0.15/4.8)G
L = (0.20/6.4)G
L = (0.25/8.0)G
Simplifying the fractions gives us:
L = (1/32)G
L = (1/32)G
L = (1/32)G
L = (1/32)G
L = (1/32)G
Therefore, we can conclude that the relationship between L (amount of oil) and G (amount of gasoline) is:
L = (1/32)G
So, the answer to the question "G = 32L" is correct.
What’s the answer to my question
The correct answer to your question is:
G = 32L