A two-digit number less than 80 and greater than 65 is divisible by 2 and 9. Name the number.
The number that satisfies all the given conditions is 72.
To find the two-digit number that is less than 80 and greater than 65 and is divisible by both 2 and 9, we can list down all the two-digit numbers greater than 65 and less than 80 and check if each number satisfies the conditions.
The two-digit numbers that satisfy the condition of being divisible by 2 are: 66, 68, 70, 72, 74, 76, 78.
Out of these numbers, we will find the numbers that are divisible by 9. The only number that is divisible by both 2 and 9 is 72.
Therefore, the two-digit number that is less than 80 and greater than 65 and is divisible by both 2 and 9 is 72.
To find the two-digit number that is less than 80 and greater than 65, and is divisible by both 2 and 9, you can follow these steps:
Step 1: List all the two-digit numbers between 65 and 80.
- The numbers between 65 and 80 are: 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79.
Step 2: Check if each number is divisible by both 2 and 9.
- Divisibility by 2: A number is divisible by 2 if it ends in 0, 2, 4, 6, or 8.
- Divisibility by 9: A number is divisible by 9 if the sum of its digits is divisible by 9.
Step 3: By following step 2, we can identify the two-digit number that satisfies both conditions.
- From the list above, the only number that is divisible by 2 and 9 is 72.
Therefore, the two-digit number less than 80 and greater than 65, and divisible by both 2 and 9 is 72.