What single-digit numbers besides 1 divide evenly into both 24 and 96? List your responses in order from the lowest to the highest number.

The single-digit numbers besides 1 that divide evenly into both 24 and 96 are:

2, 3, 4, 6, and 8.

Listing them in order from the lowest to the highest number, we have:

2, 3, 4, 6, 8.

To find the single-digit numbers that divide evenly into both 24 and 96, we can begin by listing the factors of each number.

Factors of 24: 1, 2, 3, 4, 6, 8, 12, 24
Factors of 96: 1, 2, 3, 4, 6, 8, 12, 16, 24, 32, 48, 96

From this list, we can identify the single-digit numbers that are common to both lists. These numbers are 1, 2, 3, 4, 6, and 8.

The numbers are already listed in order from lowest to highest, so the answer would be:
1, 2, 3, 4, 6, 8

To find the single-digit numbers that divide evenly into both 24 and 96, we can check each single-digit number and see if it divides evenly into both.

Let's go through the single-digit numbers from 2 to 9:

2: 24 ÷ 2 = 12, 96 ÷ 2 = 48. Both have no remainders.
3: 24 ÷ 3 = 8, and 96 ÷ 3 = 32. Both have no remainders.
4: 24 ÷ 4 = 6, and 96 ÷ 4 = 24. Both have no remainders.
5: 24 ÷ 5 = 4.8 (not a whole number), and 96 ÷ 5 = 19.2 (not a whole number).
6: 24 ÷ 6 = 4, and 96 ÷ 6 = 16. Both have no remainders.
7: 24 ÷ 7 = 3.4 (not a whole number), and 96 ÷ 7 = 13.7 (not a whole number).
8: 24 ÷ 8 = 3, and 96 ÷ 8 = 12. Both have no remainders.
9: 24 ÷ 9 = 2.6 (not a whole number), and 96 ÷ 9 = 10.7 (not a whole number).

Based on our calculations, the single-digit numbers besides 1 that divide evenly into both 24 and 96 are: 2, 3, 4, 6, and 8. Listing them from the lowest to highest, we have: 2, 3, 4, 6, 8.

the answer is 2,3,4,6,