What is the product of the three smallest prime numbers which are greater than 1?
The smallest prime numbers greater than 1 are 2, 3, and 5. Therefore, their product is 2 * 3 * 5 = <<2*3*5=30>>30.
To find the product of the three smallest prime numbers greater than 1, you first need to identify the three smallest prime numbers. Prime numbers are the numbers that are only divisible by 1 and themselves.
The first prime number is 2. It is the only even prime number because all other even numbers can be divided by 2.
The next prime number is 3. It is the smallest odd prime number.
The third prime number is 5. It is the next prime number following 3.
Now, you can find the product of these three prime numbers by multiplying them together:
2 * 3 * 5 = 30
Therefore, the product of the three smallest prime numbers greater than 1 is 30.
To find the product of the three smallest prime numbers greater than 1, we first need to identify these three prime numbers.
The prime numbers are integers greater than 1 that are divisible only by 1 and themselves. The first three prime numbers are 2, 3, and 5.
To find the product, we simply multiply these three numbers together:
Product = 2 * 3 * 5
Calculating this gives us:
Product = 2 * 3 * 5 = 30
Therefore, the product of the three smallest prime numbers greater than 1 is 30.