Two forces act on an object one force has a magnitude of 30n directed west, and the other force has a magnitude of 12 n directed east what is the net force on the object? A. 18n east b. 18nwest c.42n east d. 42n west
The net force on an object is found by summing up the individual forces acting on it.
Given that one force has a magnitude of 30 N directed west and the other force has a magnitude of 12 N directed east, we can subtract the magnitude of the eastward force from the magnitude of the westward force to get the net force.
Net force = 30 N - 12 N = 18 N
Since the net force is positive (18 N) and was obtained by subtracting a force directed east from a force directed west, we can conclude that the net force is directed west.
Therefore, the answer is d. 42 N west.
To find the net force on an object, we need to add the magnitudes of the forces acting on it. In this case, one force has a magnitude of 30 N directed west, and the other force has a magnitude of 12 N directed east.
Since the forces are acting in opposite directions, we subtract the smaller magnitude from the larger magnitude:
30 N - 12 N = 18 N
The net force on the object is 18 N. However, since the force with a magnitude of 30 N is directed west and the force with a magnitude of 12 N is directed east, the net force should have the direction of the larger force, which is west.
Therefore, the net force on the object is 18 N, directed west.
So, the correct answer is b. 18 N west.
To find the net force acting on an object, we need to calculate the vector sum of the individual forces.
In this case, we have one force of 30 N directed west and another force of 12 N directed east.
When adding vectors, we need to consider their directions. Since the force directed west is opposite in direction to the force directed east, we subtract their magnitudes.
30 N (west) - 12 N (east) = 18 N (west)
Therefore, the net force on the object is 18 N directed west.
So, the correct answer is b. 18 N west.