Solve the given system of linear equations by inspection. Enter 1 for one solution,2 for no solution, or 3 for infinitely many solutions
2x-7y=4
2x-7y=-4
The given system of linear equations can be rewritten as:
2x - 7y = 4 ...(Equation 1)
2x - 7y = -4 ...(Equation 2)
By comparing the coefficients of x and y in both equations, we can see that they are the same. However, the constant terms are different.
Since the coefficients of x and y are the same, but the constant terms are different, this implies that the two lines represented by the equations are parallel.
Parallel lines never intersect, which means there is no solution to the system of equations.
Therefore, the answer is 2 for no solution.
To determine the number of solutions in the given system of linear equations, let's compare the two equations:
Equation 1: 2x - 7y = 4
Equation 2: 2x - 7y = -4
By inspection, we can see that both equations have the same left-hand side (2x - 7y). However, the right-hand sides are different (4 and -4).
Since the left-hand sides are the same but the right-hand sides are different, we can conclude that there is NO solution to this system of equations.
Therefore, the answer is 2 (no solution).
To solve the given system of linear equations by inspection, we need to compare the coefficients of the variables.
Looking at the equations:
2x - 7y = 4
2x - 7y = -4
We can observe that the coefficients of both x and y are the same in both equations. This means that the equations represent parallel lines.
Since parallel lines never meet, there is no solution to the system of equations. Therefore, the answer is 2 (no solution).