A 45 kg person jumps off a diving platform 10.0 m above the water. If they reach the surface of the water at a speed of 12 ms, whatis the person's kinetic energy? Hint: Use the formula KE = ‡mo?. (3 points)
To find the person's kinetic energy, we can use the formula KE = 1/2 * m * v^2, where KE is the kinetic energy, m is the mass of the person, and v is the speed at which they reach the surface of the water.
Given:
m = 45 kg
v = 12 m/s
Plugging in the values into the formula, we get:
KE = 1/2 * 45 kg * (12 m/s)^2
= 1/2 * 45 kg * 144 m^2/s^2
= 1/2 * 45 kg * 144 m^2/s^2
= 3240 kg * m^2/s^2
Therefore, the person's kinetic energy is 3240 kg * m^2/s^2.
To find the person's kinetic energy, we can use the formula KE = 1/2 mv^2, where KE is the kinetic energy, m is the mass of the object, and v is the velocity.
Given:
m = 45 kg (mass of the person)
v = 12 m/s (velocity of the person)
Let's substitute the values into the formula to calculate the kinetic energy:
KE = 1/2 * m * v^2
= 1/2 * 45 kg * (12 m/s)^2
= 1/2 * 45 kg * 144 m^2/s^2
= 6480 kg m^2/s^2
Therefore, the person's kinetic energy is 6480 kg m^2/s^2.
To find the person's kinetic energy, we can use the formula KE = 1/2 * m * v^2, where KE represents the kinetic energy, m represents the mass, and v represents the velocity.
In this case, the mass of the person is given as 45 kg, and the velocity is given as 12 m/s. Plugging these values into the formula, we have:
KE = 1/2 * 45 kg * (12 m/s)^2
First, let's calculate the square of the velocity:
(12 m/s)^2 = 144 m^2/s^2
Now, we can calculate the kinetic energy:
KE = 1/2 * 45 kg * 144 m^2/s^2
Multiplying the numbers:
KE = 0.5 * 45 kg * 144 m^2/s^2
KE = 3240 kg*m^2/s^2
The person's kinetic energy is 3240 kg*m^2/s^2.