A 45 kg person jumps off a diving platform 10.0 m above the water. If they reach the surface of the water at
a speed of 12 mis, whatis the person's kinetic energy? Hint: Use the formula KB = 1/2 mv^2
To find the person's kinetic energy, we can use the formula K = 1/2 mv^2, where K is the kinetic energy, m is the mass of the person, and v is the speed of the person.
Given:
Mass of the person (m) = 45 kg
Speed of the person (v) = 12 m/s
Plugging in these values into the formula, we get:
K = 1/2 * 45 kg * (12 m/s)^2
Now, let's calculate the kinetic energy:
K = 1/2 * 45 kg * (12 m/s)^2
K = 1/2 * 45 kg * (144 m^2/s^2)
K = 0.5 * 45 kg * 144 m^2/s^2
K = 0.5 * 45 kg * 144 m^2/s^2
K = 3240 kg m^2/s^2
Therefore, the person's kinetic energy is 3240 kg m^2/s^2.
To find the person's kinetic energy, we can use the formula:
KE = (1/2) * m * v^2
Where:
KE = Kinetic Energy
m = mass
v = velocity
Given:
m = 45 kg (mass of the person)
v = 12 m/s (velocity)
Let's substitute the given values into the formula:
KE = (1/2) * 45 kg * (12 m/s)^2
Now, let's calculate the kinetic energy:
KE = (1/2) * 45 kg * 144 m^2/s^2
KE = 0.5 * 45 kg * 144 m^2/s^2
KE = 3240 kg * m^2/s^2
Therefore, the person's kinetic energy is 3240 kg * m^2/s^2.
To find the person's kinetic energy, we can use the formula KE = 1/2 * m * v^2, where KE represents kinetic energy, m represents mass, and v represents velocity.
First, let's convert the mass from kilograms to grams. Since there are 1000 grams in a kilogram, multiplying 45 kg by 1000 gives us 45,000 grams.
Next, we need to calculate the velocity squared. The given velocity is 12 m/s, so 12^2 = 144.
Now, we can plug in the values into the formula:
KE = 1/2 * m * v^2
= 1/2 * 45,000 g * 144 (m/s)^2
Let's convert the grams to kilograms by dividing by 1000:
= 1/2 * 45 kg * 144 (m/s)^2
Finally, we can calculate the kinetic energy:
= 32,400 J (joules)
Therefore, the person's kinetic energy is 32,400 joules.