48÷((2+6)×2)−1=
Hint: Use the order of operations (PEMDAS).
(1 point)
Responses
-12
-12
11
11
2
2
3.2
3.2
To solve this equation, we need to follow the order of operations (PEMDAS).
P stands for Parentheses, so we start by evaluating the expression inside the parentheses:
2 + 6 = 8
Next, we multiply the result of the parentheses by 2:
8 × 2 = 16
Now, we move on to the division:
48 ÷ 16 = 3
Finally, we subtract 1:
3 - 1 = 2
So, the value of the expression is 2.
To solve the given expression, we need to use the order of operations, also known as PEMDAS:
P - Parentheses (or brackets)
E - Exponents (or powers and square roots, etc)
MD - Multiplication and Division (from left to right)
AS - Addition and Subtraction (from left to right)
Let's break down the expression step by step:
48 ÷ ((2+6) × 2) - 1 =
1. Inside the parentheses, we have (2 + 6). Performing the addition, we get:
48 ÷ (8 × 2) - 1 =
2. Now we have the multiplication, 8 × 2:
48 ÷ 16 - 1 =
3. Next, we perform the division, 48 ÷ 16:
3 - 1 =
4. Finally, we subtract 1 from 3:
2
Therefore, the value of the given expression 48÷((2+6)×2)−1 is 2.