Charlie and Andie solve this problem in two different ways.
A family of 6
spent $
74
at the movie theater.
They bought $
26
worth of snacks and a ticket for each family member.
What is the price of each ticket if all tickets are the same price?
Use the drop-down menus to complete the sentences below.
Charlie solved the problem by dividing the total amount spent by the number of family members.
Andie solved the problem by subtracting the cost of snacks from the total amount spent, and then dividing the remaining amount by the number of family members.
To find the price of each ticket, we need to subtract the cost of snacks from the total amount spent at the movie theater.
Charlie's approach:
1. Subtract the cost of snacks from the total amount spent at the movie theater: $74 - $26 = $48.
2. Divide the remaining amount by the number of family members: $48 ÷ 6 = $8.
So, according to Charlie's approach, the price of each ticket is $8.
Andie's approach:
1. Divide the total amount spent at the movie theater by the number of family members: $74 ÷ 6 = $12.33 (rounded to the nearest cent).
So, according to Andie's approach, the price of each ticket is approximately $12.33.
To find the price of each ticket, we need to subtract the cost of snacks from the total amount spent at the movie theater.
Given information:
- Total amount spent at the movie theater: $74
- Cost of snacks: $26
We can find the price of each ticket by subtracting the cost of snacks from the total amount spent: $74 - $26 = $48.
Therefore, the total cost of tickets is $48, and since there are 6 family members, we can divide the total cost by the number of family members to find the price of each ticket.
So, using the formula: Price of each ticket = Total cost of tickets / Number of family members
Price of each ticket = $48 / 6 = $8.
Therefore, the price of each ticket is $8.
Both Charlie and Andie should have reached the same answer using this method.