Taliba has $
31
to spend ordering some new phone cases.
Each phone case costs $
4
, and there is also a $
7
shipping charge.
How many phone cases, n
, can Taliba buy?
Let's assume Taliba can buy n phone cases.
The cost of each phone case is $4.
Therefore, the total cost of buying n phone cases is 4n.
There is also a shipping charge of $7.
So, the total cost of buying n phone cases with shipping is 4n + 7.
Taliba has $31 to spend.
Therefore, we can set up the equation: 4n + 7 = 31.
Solving this equation, we subtract 7 from both sides: 4n = 24.
Dividing both sides by 4, we get: n = 6.
So, Taliba can buy 6 phone cases.
To determine how many phone cases Taliba can buy, we need to subtract the shipping charge from the total amount she has to spend and divide that by the cost of each phone case.
Total amount to spend = $31
Phone case cost = $4
Shipping charge = $7
Amount available for phone cases = Total amount to spend - Shipping charge
Amount available for phone cases = $31 - $7 = $24
Number of phone cases Taliba can buy = Amount available for phone cases / Phone case cost
Number of phone cases Taliba can buy = $24 / $4 = 6
Taliba can buy 6 phone cases.
To find out how many phone cases Taliba can buy, we need to determine how much money she will have left after deducting the cost of the phone cases and the shipping charge.
Step 1: Calculate the total cost of the phone cases. Since each phone case costs $4, the total cost of n phone cases will be 4n.
Step 2: Add the shipping charge of $7 to the total cost of phone cases. This gives us 4n + 7, which represents the total amount Taliba will spend.
Step 3: Subtract the total amount spent from the initial amount of money Taliba has ($31). This will give us the amount of money she will have left after making the purchase.
Mathematically, the equation can be written as:
31 - (4n + 7) = remaining money
Now, we can solve for n.
31 - 4n - 7 = remaining money
24 - 4n = remaining money
Let's assume that Taliba can buy x phone cases. So, the equation becomes:
24 - 4x = remaining money
We need to find the largest positive integer value of x that satisfies the equation.
Since each phone case costs $4, Taliba can buy x phone cases for a total cost of 4x.
So, the equation becomes:
24 - 4x = 31 - (4x + 7)
24 - 4x = 31 - 4x - 7
24 - 4x = 24 - 4x
This means that regardless of the value of n, Taliba will always have $24 left after making the purchase. Therefore, she can buy as many phone cases as she wants (within the budget) and will still have $24 left.