The amino acid serine is coded by the mRNA codon AGU. What is the base sequence of the DNA gene that originally produced this mRNA codon?(1 point)
Responses
AGU
AGU
TCA
TCA
TCC
TCC
UCA
The base sequence of the DNA gene that originally produced the mRNA codon AGU is TCA.
To determine the base sequence of the DNA gene that originally produced the mRNA codon AGU, you need to understand how RNA is transcribed from DNA.
1. Start by writing down the given mRNA codon: AGU.
2. Recall that in transcription, RNA is synthesized from a DNA template. However, there is a slight difference in the RNA bases compared to DNA bases. In RNA, uracil (U) replaces thymine (T). So, we need to convert the mRNA codon to its DNA equivalent.
3. The mRNA codon AGU is composed of three bases: A, G, and U. Since U replaces T in RNA, we can replace the U in the codon with T to obtain the corresponding DNA codon. Thus, the DNA codon would be AGT.
Therefore, the base sequence of the DNA gene that originally produced the mRNA codon AGU is AGT. So, the correct answer is AGT.
To determine the base sequence of the DNA gene that originally produced the mRNA codon AGU, we need to use the DNA codon chart.
The mRNA codon AGU corresponds to the DNA codon UCA. However, DNA contains thymine (T) instead of uracil (U). Therefore, replacing U with T gives us the base sequence of the DNA gene.
Therefore, the correct answer is TCA