Identify the error in the syntax of the following code:%0D%0A%0D%0A%0D%0Adef is_year(year):%0D%0A if year % 4 == 0:%0D%0A print('Year is divisible by 4') %0D%0A else year % 4 != 0:%0D%0A print('Year is not divisible by 4')%0D%0A%0D%0A%0D%0A(1 point)%0D%0AResponses%0D%0A%0D%0AThere should be a double modulus to check for the remainder.%0D%0AThere should be a double modulus to check for the remainder.%0D%0A%0D%0AYou cannot add a conditional statement after the else keyword.%0D%0AYou cannot add a conditional statement after the else keyword.%0D%0A%0D%0AThe print statements shall be ended with a semi-colon.%0D%0AThe print statements shall be ended with a semi-colon.%0D%0A%0D%0AThere should not be a colon after the function definition.
The error in the syntax of the code is:
- You cannot add a conditional statement after the else keyword.
The error in the syntax of the code is that there should not be a colon after the function definition. The correct syntax for the given code is:
```python
def is_year(year):
if year % 4 == 0:
print('Year is divisible by 4')
else:
print('Year is not divisible by 4')
```
So the correct option is: "There should not be a colon after the function definition."
The error in the syntax of the code is: "You cannot add a conditional statement after the else keyword."
In Python, the syntax for an if-else statement is as follows:
```python
if condition:
# code to execute if the condition is True
else:
# code to execute if the condition is False
```
In the given code snippet, there is a `year % 4 != 0` condition after the `else` statement. This is not allowed in Python. The correct syntax would be to remove the condition after the `else` statement. Here's the corrected code:
```python
def is_year(year):
if year % 4 == 0:
print('Year is divisible by 4')
else:
print('Year is not divisible by 4')
```
Additionally, the code should not have the `%0D%0A` characters at the end of each line. These characters represent linebreaks in the URL encoding format, but they should not be present in the actual code.