Solve the system of equations
x=6y-3
2x+7y=13
From the first equation, we can isolate x by adding 3 to both sides:
x + 3 = 6y
x = 6y - 3
Substitute this expression for x in the second equation:
2(6y - 3) + 7y = 13
12y - 6 + 7y = 13
19y - 6 = 13
19y = 19
y = 1
Substitute y = 1 back into the first equation to solve for x:
x = 6(1) - 3
x = 6 - 3
x = 3
No give numbers like this
(Number,Number)
The solution to the system of equations is (3, 1).
8x-3y=-22
y=10+4x
To solve the system of equations using substitution, we can start by substituting the value of y from the second equation into the first equation:
y = 10 + 4x
8x - 3(10 + 4x) = -22
8x - 30 - 12x = -22
Combine like terms:
-4x - 30 = -22
Add 30 to both sides:
-4x = 8
Divide both sides by -4:
x = -2
Now substitute the value of x back into the second equation to solve for y:
y = 10 + 4(-2)
y = 10 - 8
y = 2
Thus, the solution to the system of equations is (-2, 2).
To solve the system of equations, we can use the method of substitution.
From the first equation, we have x = 6y - 3.
We can substitute this value of x into the second equation:
2(6y - 3) + 7y = 13
Simplifying, we get:
12y - 6 + 7y = 13
Combining like terms, we have:
19y - 6 = 13
Adding 6 to both sides, we get:
19y = 19
Dividing both sides by 19, we have:
y = 1
Now, we can substitute this value of y back into the first equation to find x:
x = 6(1) - 3
x = 6 - 3
x = 3
Therefore, the solution to the system of equations is x = 3 and y = 1.
To solve the system of equations:
Step 1: Substitute the value of x from the first equation into the second equation.
x = 6y - 3 ---(Equation 1)
2x + 7y = 13 ---(Equation 2)
Substitute x = 6y - 3 into Equation 2:
2(6y - 3) + 7y = 13
Step 2: Simplify the equation and solve for y.
12y - 6 + 7y = 13
19y - 6 = 13
19y = 13 + 6
19y = 19
y = 19 / 19
y = 1
Step 3: Substitute the value of y back into Equation 1 to solve for x.
x = 6y - 3
x = 6(1) - 3
x = 6 - 3
x = 3
Therefore, the solution to the system of equations is x = 3 and y = 1.