Melissa bought 6 CDs that were each the same price. Including sales tax, she paid a total of $81.60. Of that total, $4.80 was tax. What was the price of each CD before tax?
Let X be the price of each CD before tax.
The total price of the CDs before tax is 6 CDs * X = <<6*X=6X>>6X.
Melissa paid $81.60 - $4.80 = $<<81.6-4.8=76.8>>76.8 for the CDs without tax.
Thus, 6X = $76.80.
Thus, the price of each CD before tax is X = $76.80 / 6 = $<<76.80/6=12.8>>12.8. Answer: \boxed{12.80}.
To find the price of each CD before tax, we need to subtract the tax from the total amount paid and divide it by the number of CDs purchased.
Total amount paid = Price per CD * Number of CDs + Tax
$81.60 = Price per CD * 6 + $4.80
Now, let's solve for the Price per CD:
Subtract $4.80 from both sides:
$81.60 - $4.80 = Price per CD * 6
$76.80 = Price per CD * 6
Divide both sides by 6:
$76.80 / 6 = Price per CD
The price of each CD before tax is $12.80.
To find the price of each CD before tax, we need to subtract the sales tax from the total amount paid and then divide the result by the number of CDs.
First, subtract the tax amount ($4.80) from the total amount paid ($81.60):
$81.60 - $4.80 = $76.80
Now, we need to divide this amount by the number of CDs, which is 6:
$76.80 / 6 = $12.80
Therefore, the price of each CD before tax is $12.80.