How can you tell from looking at a nuclear reaction that fission has taken place?(1 point)

Responses

The right side of the equation will contain two or more nuclei that are smaller than one on the left side.
The right side of the equation will contain two or more nuclei that are smaller than one on the left side.

The total number of protons and neutrons be greater on the right side of the equation than on the left side.
The total number of protons and neutrons be greater on the right side of the equation than on the left side.

The total number of protons will be the same on the left and right sides of the equation.
The total number of protons will be the same on the left and right sides of the equation.

The left side of the equation will contain two or more nuclei that are smaller than one on the right side.

The right side of the equation will contain two or more nuclei that are smaller than one on the left side.

To determine if fission has taken place in a nuclear reaction, there are a few key things to look for:

1. The right side of the equation will contain two or more nuclei that are smaller than the nucleus on the left side. This is because fission involves the splitting of a larger nucleus into smaller nuclei.

2. The total number of protons and neutrons on the right side of the equation will be greater than on the left side. Fission reactions typically release additional neutrons, which can then go on to cause further fission reactions in a chain reaction.

3. The total number of protons on the left and right sides of the equation should be the same. This is because the number of protons, or atomic number, determines the element, and in a fission reaction, the elements involved typically remain the same.

Based on these observations, the correct answer would be: "The right side of the equation will contain two or more nuclei that are smaller than one on the left side."

The correct response is:

The right side of the equation will contain two or more nuclei that are smaller than one on the left side.